Negative frequency
52K views · Aug 4, 2016 · Education
Comments · 23
@threedgmh · 8 years ago
The sine on the negative side would be flipped and flow in a mirrored direction, you have them both in the same direction, but positive and negative are the same poles, but opposites, which would be a mirror image of the other going the opposite way, like reading a sign in a mirror, the words are backwards.
5
@shdi7312 · 4 years ago
the direction of e^(-jwt) is wrong, it should be in the direction of e^(jwt) mirrored around x-axis.
3
@DarkMoonLilith7 · 9 years ago
thanks
@autmanmansour6996 · 8 years ago
I don't agree that e-jwt evaporates here because eventually to get the cosine value you will need to add up the two exponential values and then divide them by 2.
1
@curtpiazza1688 · 3 years ago
Makes sense! 😅
@poiuwnwang7109 · 5 years ago
nice
@gamingwithdad5774 · 5 years ago
Can you please explain what the purpose of graphing a negative frequency with phasors when negative frequencies do not actually exist? What happens when a computation ends up with a negative frequency?
1
@SGTDUBSY · 5 years ago
Would it be possible for light to redshift enough to become a negative frequency? For instance, near the event horizon of a black hole.
1
@97m_it · 3 years ago
What would happen to sine wave ?
@MaarioneteSR · 10 years ago
isn't ω the angular speed? I'm kinda lost since he said it was frequency, and from that we could take the cosine of ω*t since it's dimensionless. From circular motion I learned that θ = ω*t, I'm not sure if I missed something or this is indeed confusing
@shinnufatima7631 · 8 years ago
Can anyone elaborate what is the need of converting to S domain ? what are advantages of doing that
@louiswilliams8534 · 3 years ago
i think i understand
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