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Learn How to Think Like Gauss

14K views · May 16, 2026 · Science & Technology

Comments · 52

  • @CandelightEdits · 4 months ago

    I really like people who appreciate the beauty of Mathematics rather than thinking its a burden ❤

    18

  • @arijin · 4 months ago

    I teach mostly low level math at a technical college, and I always insist to my students that they need to understand, not just mimic. I’m an overexplainer in life in general, and that makes my classes very thorough. They love it. The feedback I get the most is that I was the first one to convince them they weren’t bad at math and got them to understand. <br><br>So I definitely agree with the POV here. Understanding is everything. Memorization, mimicry, and algorithmic problem solving (“when you see this, do this”) is unmathematical.

    10

  • @feardiagh · 4 months ago

    I love Bessis&apos; book. Intuition and creativity are the tools of mathematics. It&apos;s sad that our pedagogy scares so many creative people away.

    3

  • @TheDelwish · 4 months ago (edited)

    I derived this formula in a similar way back in school but with a combinatorial sense.<br>Imagine 101 people. Draw a 101 by 101 square. Each cell represents a possible directed connection from one person to another, person A points to person B.<br>So there are 101 × 101 cells. But the diagonal cells are useless here, because they mean a person paired with themselves. So we remove those 101 diagonal cells.<br>Now we have:<br>101 × 101 - 10<br>Every real pair is still counted twice: A with B and B with A<br>So we divide by 2:<br>(101 × 101 - 101) / 2<br>which is the same as:<br>101 × 100 / 2 = 5050<br>And this is exactly the sum 1 + 2 + ... + 100, because we can count the same pairs row by row, after removing the diagonal and keeping only one half of the square, the rows contain 100, 99, 98, ... 1 cells(This also has a combinatorial meaning, if we count pairs without repetition, then person 1 has 100 possible pairs, person 2 has 99, and so on)

    3

  • @cr7_jr-g7m · 4 months ago (edited)

    I would use a method : (m/2×m)+m/2 , where m is the last number in the summation , eg if it&apos;s 1 to 200 , m is 200.

    1

  • @Mr.11_13 · 4 months ago

    The probability answer is genius

    1

  • @Candelight_Music · 4 months ago (edited)

    I really like Evariste galois try making a video on him someday if you can ❤

    4

  • @ValidatingUsername · 4 months ago

    Now imagine it from zero to infinity...

    3

  • @MrSilversMathSheets · 4 months ago

    Congratulations on reaching 100 subscribers!

  • @geroldbendix1651 · 4 months ago (edited)

    I think combining calculation and geometry is the kings class of math.<br>I can&apos;t even imagine to visualize the triangle example in my mind.<br><br>Memory is the root of intellect

  • @BretFromPhilly · 4 months ago (edited)

    I did it in my head. It was 201*100. I added 0 because that makes the math easier

    1

  • @adityakhatwa8555 · 4 months ago (edited)

    As far as Gauss problem is considered. The idea is this &quot;Instead of adding up the number sequentially lets add first + last. Since we get 101 as an answer till the last number 50 +51. So instead of adding everything multiply 101 with repetation of 50. Ans we get 5050. We had total number n=100; and the number we get from adding this is n+1 so s= n(n+1)/2&quot;. All hail King Gauss.

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