Is this the (2nd) WORST Math Homework Ever?
213K views · Nov 25, 2025 · Education
Comments · 1K
@WrathofMath · 10 months ago · pinned
Do you think it's ever remotely acceptable to have an improper fraction in a mixed number?<br><br>🛍 Check out my math fashion brand! <a href="https://mathshion.com/">https://mathshion.com/</a><br>❤ Join the channel to get exclusive and early videos, original music, math lectures, and more!<br><a href="https://www.youtube.com/channel/UCyEKvaxi8mt9FMc62MHcliw/join">https://www.youtube.com/channel/UCyEKvaxi8mt9FMc62MHcliw/join</a>
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@antony1458 · 10 months ago
Again, Another homework that should be solved by a computer science student rather than 5th graders
3.1K
@xation6048 · 10 months ago (edited)
sir, another "use the digits 1-9, each exactly once" homework has hit the math subreddit
2.2K
@Moist_Richard279 · 10 months ago
Having an improper fraction in a mixed number is wild. Just use one or the other.
1.5K
@midn8588 · 10 months ago
I would have eliminated unreduced fractions and been left with 0 legal solutions lol
1.6K
@NathShapeless · 10 months ago
Interesting that there are zero solutions that both use only proper fractions <i>and</i> are in lowest terms.
931
@azuarc · 10 months ago (edited)
I paused and said "hey, this looks easy enough." Then I realized that the fraction part of a mixed number probably needs to be a proper, non-reducable fraction...and suddenly it got a whole lot harder because the options for denominators were incredibly restricted.<br><br>Edit: Oh, turns out that those restrictions make it literally impossible.
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@Tyler.8046 · 10 months ago
Honestly, this is such a better problem, compared to the other. Notably, the solution guide didn't make me have a stroke.
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@memedudech.1921 · 10 months ago
Ah yes I do often use my 6 1/7tbsp measuring spoon.
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@VirtualMarmalade · 10 months ago (edited)
<a href="https://www.youtube.com/watch?v=7X3jG5X4VIs&t=106">1:46</a> 6¹/⁷ tbsp is such a heinous measurement oh my god cursed cursed cursed cursed
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@darthswag · 10 months ago
So, if there is no improper fractions, and if all fractions are reduced, then there are 0 solutions.
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@quigonkenny · 10 months ago
<a href="https://www.youtube.com/watch?v=7X3jG5X4VIs&t=487">8:07</a> The second one, in addition to being improper, is just flat out wrong.
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