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Only 1% Can Solve This Math Problem

63K views · Feb 27, 2026 · Science & Technology

Comments · 208

  • @denvercheddie · 7 months ago · pinned

    <a href="https://www.youtube.com/watch?v=o7SaAdAyUU0&amp;t=391">6:31</a> You could have gotten the answer of 2 much faster. Recognize that a+a^2+a^3 = a*0 = 0. Same with beta. Then that leaves us with 1+1.

    42

  • @andresgradilla146 · 7 months ago

    I went one step further in exercise 2.<br><br>When you have 1 + alpha + alpha² + alpha³ + 1 + beta + beta² + beta³ just take out alpha and beta as common term and you get<br><br>1+alpha(1+alpha+alpha²) +1+beta(1+beta+beta²) and you can simplify both sums in parentheses to 0 which multiplied by either alpha or beta will still be 0, so you end up with 1+1, which will of course be 2.

    5

  • @Johnny-w5q3k · 7 months ago

    x^(n+1) - 1 = (x - 1)(x^n + ... x^2 + x + 1)<br><br>is useful trick to remember

    35

  • @ai314159 · 7 months ago

    Missed opportunity to discuss cyclotomic polynomials and roots of unity.

    37

  • @frendlyleaf6187 · 7 months ago (edited)

    All you need is x^5 = 1 AND x ≠ 1 using these two the question is trivial. And obviously 12.

    49

  • @old_grey_cat · 7 months ago

    I think the piece would have been improved by pointing out that the starting equation means we are dealing with complex numbers, so we won&apos;t &nbsp;try to solve for X itself.

    2

  • @renesperb · 6 months ago

    Write the equation as (x^5-1)/(x-1)=0 .Hence if x≠ 1 we have x^5 = 1 . The rest is as discussed in the video.

  • @ADITYA2009-j2u · 6 months ago

    Learning-multiply with a specific term to eqn and subtract it with previous eqn to get the required value<br><br>Condition eqn should not contain coefficients so that terms should be cancelling.

    1

  • @YennetiDhiraj · 7 months ago

    It was fun and an easy one, seemed hard at first glance but became easy as soon as I saw the given equation properly. Thanks for bringing questions for us to solve.

    2

  • @tommcintyre8391 · 7 months ago

    I could see it, but not by being smart - only by being quite familiar with the trick of multiplying any geometric series of powers of x by (x-1) to collapse it to a binomial.<br>Fun problems!

    3

  • @Mc_Rbx-01 · 3 months ago

    The solution to it is very beautiful wow. Very good video

  • @S8EdgyVA · 7 months ago

    I can’t believe I tried to factor out the quadratic t^2+5t+6 (I was struggling with the problem and tried to factor out the bottom expression) as (t-2)(t-3) instead of (t+2)(t+3)

    1

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