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Only 1% Can Solve For The Area. High IQ Test Puzzle

188K views · Jan 17, 2026 · Science & Technology

Comments · 599

  • @StLouisKeith · 8 months ago

    This is relatively simple compared to some of your prior geometry problems.

    457

  • @pk2712 · 8 months ago

    Pretty low bar for the statement only a genius can solve this problem.

    328

  • @dariodiluciano9443 · 8 months ago

    Surprisingly easy for a Mind your Decision geometry problem

    85

  • @AnotherDuck · 8 months ago

    One of those puzzles that seem hard, but just magically works out to a very elegant solution if you just go through the steps that seem logical.

    100

  • @luukderie8344 · 8 months ago

    The 1% is grossly underestimated. This could be a standard exercise for geometry in high school in europe

    78

  • @kingcobras3329 · 8 months ago

    Very easy

    169

  • @robshaw2639 · 8 months ago

    With no constraint on the aspect of the rectangle, you can just call it a square -  implicit in the problem is that answer only depends on the area, not the aspect ratio

    291

  • @AdamHegazy-q9j · 8 months ago

    If you made the sides of the rectangle 2x and 2y will be easier later

    54

  • @pratik4096 · 8 months ago

    A lot of people are commenting saying that they just assumed the rectangle's aspect ratio to be something of their choosing since it isn't given, but this is a mathematically incorrect approach. You need to prove that the solution is independent of the aspect ratio. To assume that it is so because the question must have a singular solution is mathematically unsound reasoning.

    51

  • @WontTrout · 8 months ago

    THIS is from Mensa?!?! Na, this took me less than a minute...

    43

  • @laszlovida90 · 8 months ago

    Started exactly like this, but stopped in the middle and restarted with new labels. <br>If you define the rectangle sides as 2x and 2y , then xy=1 and every (parenthesis)square suddenly looks super comfortable. :)

    3

  • @TunaAlert · 8 months ago

    I went with the easiest case of the rectangle being a 2x2 square and calculated it that way after realizing that the ratio of the rectangle is variable. When a question like this is posed this kind of approach is often a good one that saves time and effort, but it&apos;s not rigorous.

    3

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