Matrix multiplication as composition | Chapter 4, Essence of linear algebra
4.4M views · Aug 8, 2016 · Education
Comments · 3.3K
@akmalrazak9686 · 6 years ago
Learning matrix in high school was like learning how to construct a sentence but never know it was for communication
8.3K
@wertnick86 · 7 years ago
20 years after first being exposed to matrices, and getting a computer engineering degree, I finally understand matrix multiplication.
4.4K
@strengthinnumberstutoring61 · 4 years ago
I have a degree in math and actually run a successful mathematics tutoring service. I have never seen anything like these videos. They are incredibly intuitive. Every time - every time! - there is some step where I say “oh, but you’re not paying attention to <b>this</b> detail or <b>that</b> detail,” within seconds Grant addresses exactly the misgiving I have by saying “now, it may seem like we’re being a bit dishonest here,” or some other welcome mixed dose of humility, honesty, and humor. Thank God for this channel - a rare glimpse into what it is like for mathematics to be considered a subject worthy of human inquiry.
1.3K
@frontmandylan2150 · 5 years ago
This series is without a doubt the best educational content I've ever come across on the internet. I can't thank you enough for these videos
1.7K
@josephvallillo1219 · 9 years ago
I have a masters degree in engineering and this series is blowing my mind.
5K
@jojodasjojo · 1 year ago
There where a lot of moment of me just being absolutely stunned by how intuitively you can explain the concepts!
177
@fluxtwee2804 · 7 years ago
I love the small details like how Composition was colored to look like it is a composition of a rotation and a shear.
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@GreenDayxRock1 · 10 years ago
So for everyone else that had trouble with his "honest to god proof"... I've taken a number of courses in linear algebra and many proof courses, and found the same hole in his explanation. Here's what he means though, he just left out a crucial intermediary in his proof:<br> <br>A(BC) means apply the overall effect of BC and then A. Of course, the overall effect of BC is equivalent to applying C then B based on what he explained earlier in the video. So we have just shown that applying the overall effect of BC and then A is the same as applying C, then B, then A. Similarly, (AB)C means apply C then the overall effect of AB. But applying overall effect of AB is equivalent to applying B then A. So we can just apply C then B then A and get the same thing. Since both A(BC) and (AB)C decompose to applying C then B then A, we have that A(BC) = (AB)C
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@JustaChillConlanger · 1 year ago
<a href="https://www.youtube.com/watch?v=XkY2DOUCWMU&t=576">9:36</a> color transfomation
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@raviiit6415 · 8 years ago
My ears feeling educated
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@alfredwong1489 · 8 years ago
"Good explanation > Symbolic proof "<br>Exactly. I've been screaming this in my mind every time I see math. If my middle school teachers taught like this I wouldn't have hated math.<br>Thank you so much :D
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@Sentas9 · 3 years ago
Our professor at our university in Germany suggested your YouTube channel to us because he couldn't properly represent the 3 dimensions on the board, and it has been very helpful to me. Thank you for your videos.
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