Lesson 2 - Source Transformations, Part 2 (Engineering Circuits)
111K views · Aug 19, 2016 · Education
Comments · 42
@eccleziassenat3262 · 6 years ago
Man we need the rest of it ahaahahaha.
88
@thabisombingo6269 · 3 years ago
U left us hanging
32
@santiago_bat · 2 years ago
bro literally edge us 💀💀💀
19
@cecilianyangu6790 · 6 years ago
Why did it cut ...<br>Where is the complete video
25
@JeremyChung · 3 years ago
I also got 0.825 A
9
@deetchu9998 · 8 years ago
Why didn't you complete the problem????
13
@madhurikamala7677 · 8 years ago
Answer 0.825Amp
10
@estevangtz6041 · 6 years ago (edited)
Coming to comments for video solutions? Lol same .... after video paused through parallel series of resistors on right side then a source transformation on right side then did mesh equations. You can cancel out one variable and I got i1=0.825A . Looking at other comments that's what others got, but yea. Goodluck with your exam
6
@arisbautista4510 · 1 year ago
If you guys haven't solved it yet, the people that calculated here just solved for Req of 20||5, resulting to 4 ohms. With the 4 ohms, we then do source transformation with the 8A again, so 8A*4 ohms will result to 32v.<br><br>After that, perform mesh equivalent on the circuit, so by now we have 6v on the left side and 32v on the right side, both facing upwards, but we will assume the current is flowing clockwise.<br><br>The Mesh 1 equation will be:<br>34i1-30i2=6v<br><br>The Mesh 2 equation will be:<br>-30i1+50i2=-32v<br><br>Now when you use the elimination method, we can multiply 5 on the Mesh 1, and 3 on the Mesh 2 to eliminate the i2. Thus,<br><br>170i1-150i2=30v<br>-90i1+150i2=-96v<br><br>Now from here solve for i1<br><br>80i1=-66v<br><br>U will get i1=-0.875 which is really negative I don't know how it is positive with the others.<br><br>Hope this helps!
15
@arghyabanerjee3044 · 5 years ago
Is it possible without source transformation and without applying kcl/kvl solve this equation? only using ohm's law does this equation solve.if possible then please make a video to solve only using ohm's law.
@rodericksibelius8472 · 2 years ago
What if we reverse the polarity of one voltage source?
@osamamahmoud7170 · 4 years ago
Hello , I wanna thank you I really learnt a lot from your great lessons sir , It's Osama Mahmoud From Egypt Here
3
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