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Let's Invent Two-Dimensional Multiplication

63K views · Nov 9, 2024 · Education

Comments · 205

  • @WrathofMath · 1 year ago (edited) · pinned

    Join the channel to get exclusive and early videos, original music, lecture videos, and more!<br><a href="https://www.youtube.com/channel/UCyEKvaxi8mt9FMc62MHcliw/join">https://www.youtube.com/channel/UCyEKvaxi8mt9FMc62MHcliw/join</a><br>🛍 Check out my math fashion brand: <a href="https://mathshion.com/">https://mathshion.com/</a><br><br>More Math Chats: <a href="https://www.youtube.com/playlist?list=PLztBpqftvzxXQDmPmSOwXSU9vOHgty1RO">https://www.youtube.com/playlist?list=PLztBpqftvzxXQDmPmSOwXSU9vOHgty1RO</a>

    44

  • @kent631420 · 1 year ago

    bro discovered the dot product 🔥🔥🔥

    393

  • @glassman96 · 1 year ago

    Why is the math saying lul at me stop laughing at me math

    202

  • @calebdupree3564 · 1 year ago

    i turned on the video thinking “wouldn’t it just be like multiplying matrices?” and then you started talking and i was like “i guess not” and then you kept talking and i was like “it is just like multiplying matrices”

    6

  • @viniciusares321 · 1 year ago

    Good dot product explanation but, a real 2D multiplication should result in a 2D result, and everything be still contained in a 2D plane without third dimension

    44

  • @douglasmagowan4918 · 1 year ago

    Alternatively, you can define two dimensional multiplication such that we multiply the magnitudes and add the arguements. &nbsp;This is isomorphic to the multiplication of the complex numbers, and is a natural extension of multiplication of the real numbers.

    10

  • @angeldude101 · 1 year ago (edited)

    Multiplying 2D numbers is easy: (ax + by)(cx+ dy) = acx² + adxy + bcyx + bdy². The problem is that the result we got is 4D, but we&apos;d probably want the result to stay in 2D. For starters, let&apos;s define x as 1, because a multiplicative identity is useful, which gives us ac + (ad + bc)y + bdy². That shaved off a dimension of the result, but we still ended up with a trinomial rather than a binomial, so we just have to pick something for y² to be. Since scalar factors are mostly irrelevant, that really only leaves 5 options: y² ∈ { 0, 1, -1, y, -y }. Choosing y² = -1 gives the well-known complex numbers. Choosing y² = 1 gives the less well-known hyperbolic numbers (more often called the worse name of &quot;split-complex numbers&quot;). Choosing y² = 0 gives the dual numbers. I&apos;m actually not sure what would happen when choosing y² = ±y, but it&apos;s possible that it&apos;d actually just result in a shifted or skewed copy of one of the prior three.

    148

  • @slushpupp1 · 1 year ago

    <a href="https://www.youtube.com/watch?v=04IAZCONqro&amp;t=385">6:25</a> OH YEAH, VECTOR!!!

    4

  • @Blox-Beam · 1 year ago

    <a href="https://www.youtube.com/watch?v=04IAZCONqro&amp;t=214">3:34</a> thats basically what modulus of a complex number is

    29

  • @notthecheatr23 · 1 year ago

    This is important stuff but where it really gets beautiful (and starts to seem much more systematic) is when you get to geometric algebra... perhaps that one&apos;s considered a higher barrier to entry, but it does a great job of tying together a lot of &quot;weirdness&quot; like dot and cross products, complex numbers and generalizing to higher dimensions, etc.

    12

  • @Dani0x1B · 1 year ago

    Freya Holmer made a video about vector multiplication a while ago that&apos;s very well explain and I recommend it to anyone who enjoyed this one

    4

  • @nicholasleclerc1583 · 6 months ago

    Basically <b>the &quot;Geometric Product&quot;,</b> or an introduction to the intuition &amp; the &quot;main idea&quot; (&quot;)behind(&quot;)

    4

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