Let's Invent Two-Dimensional Multiplication
63K views · Nov 9, 2024 · Education
Comments · 205
@WrathofMath · 1 year ago (edited) · pinned
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@kent631420 · 1 year ago
bro discovered the dot product 🔥🔥🔥
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@glassman96 · 1 year ago
Why is the math saying lul at me stop laughing at me math
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@calebdupree3564 · 1 year ago
i turned on the video thinking “wouldn’t it just be like multiplying matrices?” and then you started talking and i was like “i guess not” and then you kept talking and i was like “it is just like multiplying matrices”
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@viniciusares321 · 1 year ago
Good dot product explanation but, a real 2D multiplication should result in a 2D result, and everything be still contained in a 2D plane without third dimension
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@douglasmagowan4918 · 1 year ago
Alternatively, you can define two dimensional multiplication such that we multiply the magnitudes and add the arguements. This is isomorphic to the multiplication of the complex numbers, and is a natural extension of multiplication of the real numbers.
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@angeldude101 · 1 year ago (edited)
Multiplying 2D numbers is easy: (ax + by)(cx+ dy) = acx² + adxy + bcyx + bdy². The problem is that the result we got is 4D, but we'd probably want the result to stay in 2D. For starters, let's define x as 1, because a multiplicative identity is useful, which gives us ac + (ad + bc)y + bdy². That shaved off a dimension of the result, but we still ended up with a trinomial rather than a binomial, so we just have to pick something for y² to be. Since scalar factors are mostly irrelevant, that really only leaves 5 options: y² ∈ { 0, 1, -1, y, -y }. Choosing y² = -1 gives the well-known complex numbers. Choosing y² = 1 gives the less well-known hyperbolic numbers (more often called the worse name of "split-complex numbers"). Choosing y² = 0 gives the dual numbers. I'm actually not sure what would happen when choosing y² = ±y, but it's possible that it'd actually just result in a shifted or skewed copy of one of the prior three.
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@slushpupp1 · 1 year ago
<a href="https://www.youtube.com/watch?v=04IAZCONqro&t=385">6:25</a> OH YEAH, VECTOR!!!
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@Blox-Beam · 1 year ago
<a href="https://www.youtube.com/watch?v=04IAZCONqro&t=214">3:34</a> thats basically what modulus of a complex number is
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@notthecheatr23 · 1 year ago
This is important stuff but where it really gets beautiful (and starts to seem much more systematic) is when you get to geometric algebra... perhaps that one's considered a higher barrier to entry, but it does a great job of tying together a lot of "weirdness" like dot and cross products, complex numbers and generalizing to higher dimensions, etc.
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@Dani0x1B · 1 year ago
Freya Holmer made a video about vector multiplication a while ago that's very well explain and I recommend it to anyone who enjoyed this one
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@nicholasleclerc1583 · 6 months ago
Basically <b>the "Geometric Product",</b> or an introduction to the intuition & the "main idea" (")behind(")
4
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